Integrand size = 13, antiderivative size = 143 \[ \int \sin (a+b x) \tan (c+d x) \, dx=\frac {i e^{-i (a+b x)}}{2 b}+\frac {i e^{i (a+b x)}}{2 b}-\frac {i e^{-i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,-\frac {b}{2 d},1-\frac {b}{2 d},-e^{2 i (c+d x)}\right )}{b}-\frac {i e^{i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,\frac {b}{2 d},1+\frac {b}{2 d},-e^{2 i (c+d x)}\right )}{b} \]
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Time = 0.13 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {4653, 2225, 2283} \[ \int \sin (a+b x) \tan (c+d x) \, dx=-\frac {i e^{-i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,-\frac {b}{2 d},1-\frac {b}{2 d},-e^{2 i (c+d x)}\right )}{b}-\frac {i e^{i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,\frac {b}{2 d},\frac {b}{2 d}+1,-e^{2 i (c+d x)}\right )}{b}+\frac {i e^{-i (a+b x)}}{2 b}+\frac {i e^{i (a+b x)}}{2 b} \]
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Rule 2225
Rule 2283
Rule 4653
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {1}{2} e^{-i (a+b x)}-\frac {1}{2} e^{i (a+b x)}-\frac {e^{-i (a+b x)}}{1+e^{2 i (c+d x)}}+\frac {e^{i (a+b x)}}{1+e^{2 i (c+d x)}}\right ) \, dx \\ & = \frac {1}{2} \int e^{-i (a+b x)} \, dx-\frac {1}{2} \int e^{i (a+b x)} \, dx-\int \frac {e^{-i (a+b x)}}{1+e^{2 i (c+d x)}} \, dx+\int \frac {e^{i (a+b x)}}{1+e^{2 i (c+d x)}} \, dx \\ & = \frac {i e^{-i (a+b x)}}{2 b}+\frac {i e^{i (a+b x)}}{2 b}-\frac {i e^{-i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,-\frac {b}{2 d},1-\frac {b}{2 d},-e^{2 i (c+d x)}\right )}{b}-\frac {i e^{i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,\frac {b}{2 d},1+\frac {b}{2 d},-e^{2 i (c+d x)}\right )}{b} \\ \end{align*}
Time = 2.08 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.81 \[ \int \sin (a+b x) \tan (c+d x) \, dx=-\frac {i e^{-i (a+b x)} \left (-1-e^{2 i (a+b x)}+2 \operatorname {Hypergeometric2F1}\left (1,-\frac {b}{2 d},1-\frac {b}{2 d},-e^{2 i (c+d x)}\right )+2 e^{2 i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,\frac {b}{2 d},1+\frac {b}{2 d},-e^{2 i (c+d x)}\right )\right )}{2 b} \]
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\[\int \sin \left (x b +a \right ) \tan \left (d x +c \right )d x\]
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\[ \int \sin (a+b x) \tan (c+d x) \, dx=\int { \sin \left (b x + a\right ) \tan \left (d x + c\right ) \,d x } \]
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\[ \int \sin (a+b x) \tan (c+d x) \, dx=\int \sin {\left (a + b x \right )} \tan {\left (c + d x \right )}\, dx \]
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\[ \int \sin (a+b x) \tan (c+d x) \, dx=\int { \sin \left (b x + a\right ) \tan \left (d x + c\right ) \,d x } \]
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\[ \int \sin (a+b x) \tan (c+d x) \, dx=\int { \sin \left (b x + a\right ) \tan \left (d x + c\right ) \,d x } \]
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Timed out. \[ \int \sin (a+b x) \tan (c+d x) \, dx=\int \sin \left (a+b\,x\right )\,\mathrm {tan}\left (c+d\,x\right ) \,d x \]
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